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A subdivider owns 60 acres of land and wishes to subdivide into 25,000 square-foot lots. The law requires that 300,000 square feet be allowed for streets.

What is the maximum number of lots to be obtained from this site?

A) 78
B) 56.5
C) 107
D) 92.5

User Noveyak
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1 Answer

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Final answer:

The maximum number of 25,000 square-foot lots that can be obtained from a 60-acre site, after accounting for streets, is 92. This is calculated by converting acres to square feet, subtracting the area for streets, and dividing by the lot size.

Step-by-step explanation:

To determine the maximum number of 25,000 square-foot lots that can be obtained from a 60-acre site, considering that 300,000 square feet must be allowed for streets, we approach the problem with the following steps:

  1. Convert acres to square feet for the total land area. (1 acre = 43,560 square feet)
  2. Subtract the square footage required for streets from the total land area.
  3. Divide the remaining square footage by the size of each lot to get the total number of lots.

Step 1: Total land area in square feet = 60 acres * 43,560 square feet/acre = 2,613,600 square feet.

Step 2: Land area available for lots = 2,613,600 square feet - 300,000 square feet (for streets) = 2,313,600 square feet.

Step 3: Maximum number of lots = 2,313,600 square feet / 25,000 square feet/lot = 92.544 lots.

Since partial lots are not typically feasible in land development, we round down to the nearest whole number.

The maximum number of lots is therefore 92.

User Jonatan Ivanov
by
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