Final answer:
The maximum number of 25,000 square-foot lots that can be obtained from a 60-acre site, after accounting for streets, is 92. This is calculated by converting acres to square feet, subtracting the area for streets, and dividing by the lot size.
Step-by-step explanation:
To determine the maximum number of 25,000 square-foot lots that can be obtained from a 60-acre site, considering that 300,000 square feet must be allowed for streets, we approach the problem with the following steps:
- Convert acres to square feet for the total land area. (1 acre = 43,560 square feet)
- Subtract the square footage required for streets from the total land area.
- Divide the remaining square footage by the size of each lot to get the total number of lots.
Step 1: Total land area in square feet = 60 acres * 43,560 square feet/acre = 2,613,600 square feet.
Step 2: Land area available for lots = 2,613,600 square feet - 300,000 square feet (for streets) = 2,313,600 square feet.
Step 3: Maximum number of lots = 2,313,600 square feet / 25,000 square feet/lot = 92.544 lots.
Since partial lots are not typically feasible in land development, we round down to the nearest whole number.
The maximum number of lots is therefore 92.