Question

What is the concentration (m) of potassium ions in 4.57 l of a 1.63 m k 3p solution?

O 1.63 m
O 4.89 m
O 32.0 m
O 99.0 m
O 9.78 m

Answer 1

The concentration of potassium ions in a 4.57 L solution with a molarity of 1.63 M for a compound assumed to contain 3 potassium ions per formula unit is 4.89 M.

Step-by-step explanation:

To determine the concentration of potassium ions in a 4.57 L solution of 1.63 M K3P, you need to consider the stoichiometry of the compound. Since the formula K3P is not common and seems to be a typo or incorrect, we will assume that you are referring to a compound that contains 3 potassium ions per formula unit, as that would be the only way to have multiple potassium ions in a compound formula. For every 1 mole of this compound dissolved, it produces 3 moles of potassium ions. Therefore, to find the molarity of potassium ions, you will multiply the molarity of the compound by 3.

Step 1: Identify the molarity of the compound in solution, which is given as 1.63 M.

Step 2: Multiply the molarity by the number of potassium ions per formula unit (assumed to be 3 in this case).

Step 3: Calculate the potassium ion concentration by multiplying 1.63 M by 3.

Step 4: The potassium ion concentration is 1.63 M × 3 = 4.89 M.