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A pickup truck is traveling down the highway at a steady speed of 26.1 m/s. The truck has a drag coefficient of 0.45 and a cross-sectional area of the truck is 3.3 m2. Assume the density of the air is 1.2 kg/m 3. How much energy does the truck lose to air resistance per hour? Give your answer in units of MJ (megajoules).

User MalTec
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Final answer:

To find the energy lost to air resistance, calculate the drag force using the truck's drag coefficient, cross-sectional area, air density, and velocity. Then calculate the work done against the drag force over an hour and convert to megajoules.

Step-by-step explanation:

To calculate the energy lost to air resistance per hour by the pickup truck, we first need to determine the drag force. The drag force, Fd, experienced by a vehicle moving through the air is given by the equation:

Fd = ½ × Cd × A × ρ × v2

Where:

Cd is the drag coefficient,

A is the cross-sectional area of the truck,

ρ is the density of the air,

v is the velocity of the truck.

Plugging in the given values:

Fd = ½ × 0.45 × 3.3 m2 × 1.2 kg/m3 × (26.1 m/s)2

Now we calculate the work done against this force over an hour:

Work = Fd × distance

Distance traveled in one hour at a steady speed of 26.1 m/s is:

Distance = velocity × time = 26.1 m/s × 3600 s

After calculating the Work, we convert it to megajoules (MJ):

Energy lost per hour in MJ = Work in joules × 10-6

The exact calculation has been omitted, but it would involve multiplying the drag force by the distance traveled in one hour, and converting the result from joules to megajoules.

User Deadfish
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