Final answer:
The equation of a line with a slope of 1/2 that passes through the point (6, 10) in slope-intercept form is y = (1/2)x + 7.
Step-by-step explanation:
To write the equation of a line in slope-intercept form, you need to know the slope (m) and the y-intercept (b). The general formula is y = mx + b, where m is the slope and b is the y-intercept. Given that the slope is 1/2 and the line passes through the point (6, 10), we can find the y-intercept by plugging these values into the slope-intercept formula:
10 = (1/2)(6) + b
Solve for b:
10 = 3 + b
10 - 3 = b
b = 7
The equation of the line in slope-intercept form thus is y = (1/2)x + 7.
The equation of a line in slope-intercept form (y = mx + b) is defined by the slope (m) and the y-intercept (b). Given that the line has a slope of 1/2 and passes through the point (6, 10), we can substitute these values into the slope-intercept form equation.
The slope (m) is 1/2, so the equation becomes y = (1/2)x + b. To find the y-intercept, substitute the coordinates of the given point (6, 10) into the equation: 10 = (1/2)(6) + b.
Now, solve for b:
10 = 3 + b
b = 7
Therefore, the equation of the line in slope-intercept form is y = (1/2)x + 7. This equation describes a line with a slope of 1/2 that passes through the point (6, 10), and the y-intercept is 7.