Question

A piece of wood trim is 51(3)/(8)in. long. A piece 31(5)/(6) in. long is curf from it. How long is the remaining piece of wood if the cut removes (1)/(8) in. of wood?

Answer 1

After converting the measurements to improper fractions with a common denominator and accounting for the width of the cut, the remaining piece of wood is found to be 19.5 inches long.

Step-by-step explanation:

The original length of the piece of wood trim is 51(3/8) inches. When a piece measuring 31(5/6) inches is cut from it and an additional (1/8) inch is removed for the cut itself, calculations are needed to find the remaining length of the wood piece.

To find the remaining length:

Convert the mixed fractions to improper fractions: 51(3/8) becomes 411/8 and 31(5/6) becomes 191/6.

Since we are subtracting fractions with different denominators, find a common denominator, which is 24.

Convert each fraction to have the common denominator: 411/8 becomes 1233/24 and 191/6 becomes 762/24.

Now subtract the cut length and the width of the cut from the original length: 1233/24 - 762/24 - 3/24 (additional 1/8 inch for the cut, expressed as 3/24).

The remaining length is 1233/24 - 762/24 - 3/24 = 468/24 which simplifies to 19.5 inches.

Therefore, the remaining piece of wood measures 19.5 inches in length.