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What is an equation of the line that passes through (−3,−5) and (−2,−4)?

User KQS
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Final answer:

The equation of the line that passes through the points –(3, –5) and –(2, –4) is y = x - 2, found by first calculating the slope and then using the point-slope form of a line's equation.

Step-by-step explanation:

To find the equation of a line that passes through the points –(3, –5) and –(2, –4), you first need to determine the slope of the line. The slope –(m) is calculated by the formula –(m = (y2–y1)/(x2–x1)) where (x1, y1) and (x2, y2) are the coordinates of the two points. Substituting the given points into the formula gives:

m = (–4 – (–5))/((–2) – (–3)) = 1/1 = 1

Now that we have the slope, we use the point–slope form of the equation of a line, which is y – y1 = m(x – x1). Using the slope we found and one of the given points, the equation is:

y – (–5) = 1(x – (–3))

Finally, simplify to get the standard form of the line's equation:

y = x – 2

User Richard Tingle
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