Question

A force of 6 N acts on a charge of 3μC when it is placed in a uniform electric field. What is the magnitude of this electric field?

a. 18 x 10⁶ N/C

b. 2 x 10⁶ N/C

c. 0.5 x 10⁶ N/C

d. None of the above

Answer 1

The magnitude of the electric field where a force of 6 N acts on a 3µC charge is 2 × 10⁶ N/C. option b is correct

Step-by-step explanation:

Option b is correct The question asks for the magnitude of an electric field where a force of 6 N acts on a 3µC charge. To find this, we can use the formula F = qE, where F is the force, q is the charge, and E is the electric field. We solve for E as follows:

E = F / q
E = (6 N) / (3 × 10⁻¶C)
E = 2 × 10⁶ N/C

Therefore, the magnitude of the electric field is 2 × 10⁶ N/C, which is option (b).

To find the magnitude of the electric field, we can use the formula F = qE, where F is the force, q is the charge, and E is the electric field strength. In this case, we are given a force of 6 N and a charge of 3μC. Let's substitute these values into the formula:

6 N = (3μC) × E

E = 6 N / 3μC

E = 2 × 106 N/C

Therefore, the magnitude of the electric field is 2 × 106 N/C. The correct answer is option (b).