Question

Kobe bryant is shooting free throws. making or missing free throws doesn't change the probability that he will make his next one, and he makes his free throws 83 % of the time. what is the probability of kobe bryant making all of his next 6 free throw attempts? choose 1 answer: choose 1 answer:

O large{(1 - 0.83)⁶}
O large{0.83⁶}
O large{6 cdot0.83}
O large{6 cdot(1 - 0.83)}

Answer 1

The probability of Kobe Bryant making all of his next 6 free throw attempts, given an individual success rate of 83%, is 0.83^6. Option 2 is correct.

Step-by-step explanation:

The probability of Kobe Bryant making all of his next 6 free throw attempts, given that he makes free throws 83% of the time, is calculated by raising the probability of making a single free throw to the power of the number of attempts. Since each free throw is an independent event, we multiply the probability of a single event by itself for each of the 6 attempts. Therefore, we take 0.83 to the power of 6 (0.836).

The answer is 0.836, which represents the probability of making 6 free throws in a row. This option is the only one that mathematically represents the probability of consecutive successful events under the assumption of independence.

Since making or missing free throws doesn't change the probability of making the next one, each free throw attempt can be considered an independent event. The probability of making a free throw is 83%, so the probability of making all 6 attempts is:
Probability = (0.83)6