Question

If dissolving 10.0 g of ionic salt causes 100.0 ml of water to increase temperature by 24.0 °c at constant pressure, what would be the change in temperature if 27 g of the same ionic salt were used instead?

Answer 1

The expected temperature change when 27 g of the same ionic salt is dissolved in water, assuming a direct proportion between temperature change and mass of solute, would be 64.8 °C.

Step-by-step explanation:

If dissolving 10.0 g of ionic salt causes 100.0 ml of water to increase in temperature by 24.0 °C, we can use this information to predict the temperature change when a different mass of the same salt is dissolved. The temperature change is directly proportional to the mass of the salt if the specific heat capacity of the solution does not change.

Therefore, if 27 g of the salt were used, which is 2.7 times more than the initial quantity, we would expect a temperature change that is 2.7 times larger than the initial temperature change, provided that the system's capacity to absorb heat without changing its heat capacity remains the same.

Heat capacity, temperature change, and the mass of solute are the key concepts here. To calculate the predicted temperature change, we multiply the initial temperature change (24.0 °C) by the ratio of the new mass to the old mass (27 g / 10.0 g = 2.7). The expected temperature change for 27 g of salt therefore would be: 24.0 °C × 2.7 = 64.8 °C.