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If 32.0g CuCl is dissolved in a 100.0 ml of 2.00m Li₂CO₃. what is the percent yield if 17.2g Cu₂CO₃ in this experiment?

User Jtoberon
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1 Answer

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Final answer:

To calculate the percent yield, we need to compare the actual yield of the product (17.2g of Cu2CO3) to the theoretical yield of the product. The theoretical yield can be calculated using stoichiometry and the balanced equation. Finally, the percent yield can be calculated by dividing the actual yield by the theoretical yield and multiplying by 100.

Step-by-step explanation:

To calculate the percent yield, we need to compare the actual yield of the product (17.2g of Cu2CO3) to the theoretical yield of the product. The theoretical yield can be calculated using stoichiometry and the balanced equation. From the balanced equation, we can determine the molar ratio between CuCl and Cu2CO3.

Since 32.0g of CuCl was dissolved, we can convert this to moles by dividing by the molar mass of CuCl. Then, using the stoichiometric ratio, we can convert the moles of CuCl to moles of Cu2CO3 and then calculate the theoretical yield of Cu2CO3 by multiplying by the molar mass of Cu2CO3. Finally, the percent yield can be calculated by dividing the actual yield by the theoretical yield and multiplying by 100.

User Pqn
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