Final answer:
1.96 grams of copper (Cu) can produce approximately 6.64 grams of silver (Ag), assuming 100% yield, by applying stoichiometry and the molar masses of Cu and Ag.
Step-by-step explanation:
To determine how many grams of silver (Ag) can be produced from the full reaction of 1.96 grams of copper (Cu), we need to understand the stoichiometry of the reaction and use the molar mass of the reactants and products.
First, let's find the number of moles of Cu that react:
Molar mass of Cu = 63.55 g/mol
Number of moles of Cu in 1.96 g = 1.96 g / 63.55 g/mol ≈ 0.0308 mol
Next, we apply the stoichiometry of the reaction. Typically, the reaction between copper and silver nitrate is written as:
Cu + 2AgNO3 → Cu(NO3)2 + 2Ag
This shows that one mole of Cu produces two moles of Ag. Therefore, the number of moles of Ag produced will be twice the number of moles of Cu:
Number of moles of Ag = 2 * 0.0308 mol = 0.0616 mol
Finally, we calculate the mass of Ag produced:
Molar mass of Ag = 107.87 g/mol
Mass of Ag = 0.0616 mol * 107.87 g/mol ≈ 6.64 g
So, 1.96 grams of Cu can produce approximately 6.64 grams of Ag, assuming 100% yield.