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If the density of water is 0.999 g/ml at the room temperature, calculate the %error of this experiment.

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Final answer:

The density of the fluid in question, where a hydrometer with a density of 0.750 g/mL floats with 92% of its volume submerged, is approximately 0.815 g/mL.

Step-by-step explanation:

To calculate the %error of the experiment, we need to compare the experimental value with the accepted value. In this case, the accepted value for the density of water at room temperature is 1.00 g/ml. The %error can be calculated using the formula:

%error = (|experimental value - accepted value| / accepted value) x 100

Substituting the values, we get:

%error = (|0.999 - 1.00| / 1.00) x 100 = 0.1%

The question asks to find the density of a fluid in which a hydrometer with a density of 0.750 g/mL floats with 92.0% of its volume submerged. The principle behind this is Archimedes' principle, which states that the buoyant force on a submerged object is equal to the weight of the fluid that is displaced by the object.

The density of the fluid can be found using the following relationship: Density of the fluid = Density of the hydrometer / Percentage of volume submerged. So, if 92% of the hydrometer is submerged, the density of the fluid is 0.750 g/mL divided by 0.92, which equals approximately 0.815 g/mL.

User Tropicalista
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