Final answer:
KMnO4 (potassium permanganate) would NOT be expected to produce a purple or violet flame because manganese ions produce a green or pink flame that masks the color of the potassium. The correct answer is A. KMnO₄.
Step-by-step explanation:
The student asked how to identify the potassium-containing compound that would NOT produce a purple or violet flame. When potassium compounds burn, they typically produce a purple or violet flame due to the presence of the potassium ions (K+).
However, if the compound contains another element that produces a more dominant flame color, that expected purple or violet color can be masked.
In this case, the compound KMnO4 (potassium permanganate) would not produce a purple flame because the manganese (Mn) ions produce a distinctive green or pink flame that overwhelms the color of the potassium.
The other compounds listed, KNO3 (potassium nitrate), KCl (potassium chloride), and KClO4 (potassium perchlorate), would be expected to produce a purple flame as they do not contain other elements that change the flame color significantly.