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Simplify the following Boolean expressions to a minimum number of literals
xy+xy’

User Dsvensson
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Final answer:

To simplify the given Boolean expression xy+xy', we can eliminate the common term xy and use the distributive property to simplify it further.

Step-by-step explanation:

To simplify the given Boolean expression xy+xy', we can eliminate the common term xy. This leaves us with xy'+xy, which can be further simplified as xy+x(y'). Using the distributive property, we can simplify it to xy+xy', and since y+y' is always equal to 1, the final simplified expression is xy.

So, the simplified form of the Boolean expression xy+xy' is xy.

Example:

If x = true and y = false, then xy = true * false = false. Similarly, xy' = true * true = true. Therefore, xy+xy' = false + true = true, which matches the simplified expression xy.

To simplify the Boolean expression xy+xy', the common term xy is eliminated, resulting in xy'+xy. This is further simplified using the distributive property to xy+x(y'). Leveraging the fact that y+y' always equals 1, the final simplified expression is xy.

User Tikiboy
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