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Resistances of 2.0 Ω, 4.0 Ω, and 6.0 Ω and a 24-V emf device are all in parallel. What is the current in the 2.0-Ω resistor?

A. 12 A
B. 4.0 A
C. 2.4 A
D. 2.0 A
E. 0.50 A

User Tsds
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1 Answer

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Final answer:

By applying Ohm's Law, the current in a 2.0-Ω resistor connected in parallel to a 24-V emf source is calculated to be 12 A. Option A is correct.

Step-by-step explanation:

The question involves calculating the current in a 2.0-Ω resistor that's connected in parallel with other resistors to a 24-V emf (electromotive force) source. In a parallel circuit, the voltage across each resistor is the same and equal to the source voltage. By applying Ohm's Law, which states I = V/R (where I is the current, V is the voltage, and R is the resistance), you can calculate the current through the 2.0-Ω resistor by using the formula:

I = V / R = 24 V / 2.0 Ω = 12 A.

Therefore, the current in the 2.0-Ω resistor is 12 A, which corresponds to option A.

In a parallel circuit, the current splits among the branches, so the current through each resistor will be different. To find the current in the 2.0-Ω resistor, first calculate the total resistance of the circuit using the formula 1/RTotal = 1/R1 + 1/R2 + 1/R3. In this case, R1 = 2.0 Ω, R2 = 4.0 Ω, and R3 = 6.0 Ω. Plug in these values and solve for RTotal. Once you have RTotal, use Ohm's Law to find the current through the 2.0-Ω resistor by dividing the emf (24 V) by RTotal.

The current in the 2.0-Ω resistor is 12 A. Therefore, the correct option is A. 12 A.

User Leslie Chong
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