Question

It takes 35.44 mL of 0.0205 M permanganate solution to react with 25 mL of unknown oxalate solution. What is the concentration of oxalate in the unknown solution? Report your answer to four decimal places.

Answer 1

The concentration of oxalate in the unknown solution is 0.0287 M.

Step-by-step explanation:

To find the concentration of the oxalate in the unknown solution, we can use the concept of stoichiometry and the equation for the reaction between permanganate and oxalate:

2MnO4¯(aq) + 5H2C2O4(aq) + 6H+(aq) → 10CO2(g) + 2Mn2+(aq) + 8H2O(l)

From the equation, we can see that 2 moles of MnO4¯ react with 5 moles of H2C2O4. Given that it takes 35.44 mL of 0.0205 M permanganate solution to react with 25 mL of the unknown oxalate solution, we can set up the following equation:

Moles of MnO4¯ = Moles of H2C2O4

(0.0205 mol/L)(35.44 mL) = (x mol/L)(25 mL)

Solving for x, the concentration of oxalate, we get:

x = (0.0205 mol/L)(35.44 mL) / (25 mL)

x = 0.0287 M

The concentration of oxalate in the unknown solution is 0.0287 M.