Final answer:
The statement is True; in a geometric sequence with a common ratio between 0 and 1, each subsequent term is smaller than the previous, making ap smaller than an when p > n.
Step-by-step explanation:
The statement that in a geometric sequence, the term ap can be smaller than the term an is True. This can occur when the common ratio (r) of the geometric sequence is between 0 and 1. In such cases, each successive term is a fraction of the preceding term, thus each term is smaller than the previous one. For example, if a geometric sequence has a common ratio of 1/2, then a2 would be half the size of a1, a3 half of a2, and so on, making ap < an for p > n.
In a geometric sequence, the term ap 1 can be smaller than the term an. This is because a geometric sequence is a sequence of numbers where each term is found by multiplying the previous term by a constant number called the common ratio. If the common ratio is a fraction, it means that each term will be smaller than the previous term. For example, in the sequence 2, 1, 1/2, 1/4, each term is smaller than the previous term.