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What are the coordinates for the vertex of the parabola represented by the quadratic equation y = 2( x + 5)^2 − 6?

(5,−6)
(−6,−5)
(−5,−6)
(−6,5)

User Davertron
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8.4k points

2 Answers

7 votes
It’s (-5,-6). Look up vertex form, this is what it’s in. Memorize the form. It will help you.
User Infintyyy
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1 vote

Answer:


\sf (-5, -6)

Explanation:

The equation of parabola is given as:

tex]\sf y = a(x - h)^2 + k[/tex], where
\sf (h, k) are the coordinates of the vertex.

The given quadratic equation
\sf y = 2(x + 5)^2 - 6 is in the form
\sf y = a(x - h)^2 + k.

Now

Comparing it with
\sf y = a(x - h)^2 + k, we can see that
\sf h = -5 and
\sf k = -6.

Therefore, the coordinates of the vertex are
\sf (-5, -6)

What are the coordinates for the vertex of the parabola represented by the quadratic-example-1
User Brenwell
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7.7k points

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