Final answer:
In 100 mL of a 12:100 solution, there are 12 grams of active ingredient assuming the density is similar to water, making the correct answer option (d) 12 g.
Step-by-step explanation:
To determine how many grams of active ingredient 100 mL of a 12:100 solution contains, we use the ratio provided. The ratio 12:100 suggests that there are 12 grams of the active ingredient for every 100 grams of the solution.
It’s important to note that for liquid solutions, where the solute is a solid and the solvent is a liquid, mass/volume percent solutions are common. In this case, the solvent density is not given, but if we assume the density to be approximately that of water (1 g/mL), this conversion is straightforward.
Therefore, in 100 mL of solution, the mass of the active ingredient would be:
12 grams active ingredient/100 grams of solution × 100 mL of solution = 12 grams of active ingredient.
The correct answer is option (d) 12 g.