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Find the zeros of the function f(x)=0.7x^2-6x+6 Round values to the nearest hundredth (if necessary).

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Final answer:

To find the zeros of the function f(x)=0.7x^2-6x+6, apply the quadratic formula with coefficients a = 0.7, b = -6, and c = 6. This will yield two solutions for x, which, when calculated and rounded to the nearest hundredth, are approximately x ≈ 5.77 or x ≈ 1.57.

Step-by-step explanation:

To find the zeros of the function f(x)=0.7x^2-6x+6, you can use the quadratic formula:

x = √[(-b) +/- √(b^2-4ac)]/(2a)

First, identify the coefficients a = 0.7, b = -6, and c = 6. Plug these values into the quadratic formula:

x = √[(-(-6)) +/- √((-6)^2-4(0.7)(6))]/(2*0.7)

Calculating the discriminant (b^2 - 4ac):

√(36 - 16.8) = √(19.2)

Then, evaluate for both the + and - signs in the numerator:

x = (6 +/- √19.2) / 1.4

The final step is to calculate the two possible values for x, rounding to the nearest hundredth:

x ≈ 5.77 or x ≈ 1.57

User Paul Knopf
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