Question

A certain female's number 12 chromosomes both have the blue gene and number 19 chromosomes both have the long gene. As cells in her ovaries undergo meiosis, her resulting eggs (ova) may have which of the following?

A) either two number 12 chromosomes with blue genes or two with orange genes
B) either two number 19 chromosomes with long genes or two with short genes
C) either one blue or one orange gene in addition to either one long or one short gene
D) one chromosome 12 with one blue gene and one chromosome 19 with one long gene

Answer 1

The correct outcome after meiosis in the described scenario is that the resulting eggs will have one chromosome 12 with the blue gene and one chromosome 19 with the long gene.

Step-by-step explanation:

The student's question pertains to the outcomes of meiosis in human gametes, specifically the resulting alleles in the eggs (ova) of a female who carries particular genetic traits on her chromosomes. Humans have 23 pairs of chromosomes: 22 pairs of autosomes and 1 pair of sex chromosomes, with one set inherited from each parent. Meiosis results in cells that contain one of each pair of homologous chromosomes, and thus, one copy of each gene. Due to the law of segregation during meiosis, each gamete receives one of the two alleles present in a parent organism; hence, the eggs will have one allele for each trait mentioned. This suggests that the potential combinations would include one chromosome 12 with the blue gene and one chromosome 19 with the long gene.

The correct choice that describes the alleles present in a resulting egg after meiosis is:

Answer: D) one chromosome 12 with one blue gene and one chromosome 19 with one long gene.