Final answer:
The energy of a photon with a frequency of 7.39 × 1015 Hz is calculated using Planck's equation, E = hf, with Planck's constant being 6.626 × 10-34 J·s, resulting in an energy of 4.8934 × 10-19 joules per photon.
Step-by-step explanation:
To calculate the energy of a photon using Planck’s equation, we use the formula E = hf, where E represents energy in joules, h is Planck's constant, and f is the frequency of the photon in hertz (Hz). Planck's constant, h, is valued at 6.626 × 10-34 J·s. Given the frequency of the photon as 7.39 × 1015 Hz, the energy E is calculated as:
E = (6.626 × 10-34 J·s) (7.39 × 1015 Hz)
By multiplying these two values, we get:
E = (6.626 × 10-34) × (7.39 × 1015)
E = 4.8934 × 10-19 J
Therefore, the energy per photon of radiation with a frequency of 7.39 × 1015 s-1 is 4.8934 × 10-19 joules.