Final answer:
The final temperature of 2.5kg of water after adding 9400 J of heat will be 18.9°C, calculated using the specific heat capacity formula with water's specific heat capacity.
Step-by-step explanation:
Temperature Change Calculation
To calculate the temperature change of 2.5kg of water when 9400 J of heat is added, you need to use the formula:
q = mcΔT
Where:
- q is the amount of heat added (in joules)
- m is the mass of the water (in kilograms)
- c is the specific heat capacity of water (approximately 4,184 J/kg°C)
- ΔT is the change in temperature (in °C)
To solve for ΔT, rearrange the formula:
ΔT = q / (mc)
Substitute the given values:
ΔT = 9400 J / (2.5 kg × 4,184 J/kg°C)
After calculating, we find that the temperature increase ΔT is approximately 0.897°C. Adding this to the initial temperature of 18.0°C gives us the final temperature:
Final Temperature = 18.0°C + 0.897°C = 18.897°C
However, when we put this into practice and account for significant figures, we should round to a suitable level of precision. Since the least number of significant figures in the given data is three, we round it to:
Final Temperature = 18.9°C