229k views
5 votes
The Sugar Producers Association wants to estimate the mean yearly sugar consumption. A sample of 27 people reveals the mean yearly consumption to be 35 kilograms (kg) with a standard deviation of 13 kg. Assume a normal population.

a-1. What is the value of the population mean?
Population mean _____
a-2. What is the best estimate of this value?
Estimate value ______
b-1. Explain why we need to use the t distribution.
____
b-2. What assumption do you need to make?
____.
c. For a 90% confidence interval, what is the value of t? (Round the final answer to 3 decimal places.)
Value of t _____
d. Develop the 90% confidence interval for the population mean. (Round the final answers to 3 decimal places.)
Confidence interval for the population mean is _____ and ____.

User Amchacon
by
8.5k points

1 Answer

6 votes

a-1: Population mean is unknown, only estimated through confidence intervals.

a-2: Best estimate is the sample mean of 35 kg.

b-1: We use the t-distribution because the population standard deviation is unknown.

b-2: Assume normal population and random sampling.

c: Value of t is 1.699 (rounded to 3 decimal places).

d: Confidence interval is 23.04 kg to 46.96 kg.

a-1. Population Mean:

- We can't directly estimate the population mean from a single sample. The best we can do is estimate its range with a confidence interval.

a-2. Best Estimate:

- The sample mean of 35 kg is the best estimate we have for the population mean, even though it's not a definitive value.

b-1. Using the t-distribution:

- We use the t-distribution instead of the normal distribution because we don't know the population standard deviation (only the sample standard deviation). The t-distribution is similar to the normal but has "fatter tails" to account for this uncertainty.

b-2. Assumptions:

- We need to assume that the population is normally distributed (although not perfectly) and that the sample is randomly selected from the population.

c. Value of t:

- With a 90% confidence interval and 27 degrees of freedom (n-1), the t-value is approximately 1.699 (rounded to 3 decimal places). You can find this value in a t-distribution table or online calculators.

d. Confidence Interval:

- The 90% confidence interval is:

35 kg ± (t * s / √n) ≈ 35 kg ± (1.699 * 13 kg / √27) ≈ 23.04 kg to 46.96 kg

User Posthumecaver
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories