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The springs of a 1500 kg car compress 37 mm when its 81 kg driver gets into the driver's seat. What is the spring constant in N/m? Record to the nearest whole number

User OFRBG
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Final answer:

To calculate the spring constant, we apply Hooke's law using the driver's weight as the force and the car's compression as the displacement. The spring constant k is found to be approximately 21476 N/m after converting units and solving the equation.

Step-by-step explanation:

The question is asking to find the spring constant k for the car's suspension system. According to Hooke's law, F = -kx, where F is the force applied to the spring, x is the displacement caused by the force, and k is the spring constant. The negative sign indicates the restoring force the spring exerts in opposition to the applied force.

First, we convert the driver's weight to a force. Since the driver's mass is 81 kg, we calculate the gravitational force (weight) as F = mg. Using g = 9.81 m/s² (acceleration due to gravity), we have F = 81 kg × 9.81 m/s² = 794.61 N. While the displacement x provided is 37 mm, we need to convert this to meters: x = 37 mm × 10⁻³ m/mm = 0.037 m.

By using the force and displacement in Hooke's law, we can solve for the spring constant k:
k = F/x which gives us k = 794.61 N / 0.037 m ≈ 21476 N/m.

When we round to the nearest whole number, the spring constant k is approximately 21476 N/m.

User Brian Hsu
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