Question

The temperature of 600 g of liquid rises by 15°c if 300 g of the same liquid at 50°c is added to it. so what was the initial temperature of 600 g of liquid?

a. 10°C
b. 15°C
c. 5°C
d. 25°C

Answer 1

To find the initial temperature of the 600 g of liquid, we need to equate the heat gained by the 600 g of liquid to the heat lost by the 300 g of liquid. Using the formula Q = mcΔT, we can calculate the specific heat capacity (c) and determine the initial temperature. Option C is correct.

Step-by-step explanation:

To find the initial temperature of 600 g of liquid, we can use the principle of heat transfer. When 300 g of the same liquid at 50°C is added to 600 g of liquid and the temperature rises by 15°C, we can assume that the heat gained by the 600 g of liquid is equal to the heat lost by the 300 g of liquid.

We can calculate the heat gained by the 600 g of liquid using the formula:

Q = mcΔT

where Q is the heat gained, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

Using the given values, we have:

Q = (600 g)(c)(15°C)

Similarly, we can calculate the heat lost by the 300 g of liquid using the same formula. Equating the two equations, we can find the value of c, which will give us the initial temperature of the 600 g of liquid.