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Give the net ionic equation for the reaction (if any) that occurs when aqueous solutions of K2CO3 and HBr are mixed.

a. 2K⁺(aq) + CO₃²⁻(aq) + 2H⁺(aq) + 2Br⁻(aq) → H₂O(l) + CO₂(g) + 2K⁺(aq) + 2Br⁻(aq)
b. 2K⁺(aq) + 2Br⁻(aq) + 2H⁺(aq) + CO₃²⁻(aq) → H₂O(l) + CO₂(g) + 2K⁺(aq) + 2Br⁻(aq)
c. 2K⁺(aq) + CO₃²⁻(aq) + 2H⁺(aq) + 2Br⁻(aq) → H₂CO₃(s) + 2K⁺(aq) + 2Br⁻(aq)
d. 2K⁺(aq) + 2Br⁻(aq) + 2K⁺(aq) + CO₃²⁻(aq) + 2H⁺(aq) → H₂CO₃(s) + 2Br⁻(aq)

User Tamberg
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Final answer:

The net ionic equation for the reaction between K2CO3 and HBr in aqueous solution is 2K+(aq) + 2Br-(aq) + CO3^2-(aq) + 2H+(aq) → H2O(l) + CO2(g) + 2K+(aq) + 2Br-(aq). The correct answer is option b. 2K⁺(aq) + 2Br⁻(aq) + 2H⁺(aq) + CO₃²⁻(aq) → H₂O(l) + CO₂(g) + 2K⁺(aq) + 2Br⁻(aq).

Step-by-step explanation:

The net ionic equation for the reaction between aqueous solutions of K2CO3 and HBr can be represented as:

2K+(aq) + 2Br-(aq) + CO32-(aq) + 2H+(aq) → H2O(l) + CO2(g) + 2K+(aq) + 2Br-(aq)

This equation shows the formation of water, carbon dioxide, and the ions present in the original solutions.

This equation represents the acid-base neutralization reaction between carbonate ions and hydrogen ions, producing water and carbon dioxide gas.

The potassium ions (K+) and bromide ions (Br−) are spectator ions and do not participate in the reaction, hence they are not included in the net ionic equation. Therefore, the correct answer is b. 2K⁺(aq) + 2Br⁻(aq) + 2H⁺(aq) + CO₃²⁻(aq) → H₂O(l) + CO₂(g) + 2K⁺(aq) + 2Br⁻(aq).

User Garuno
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