Final answer:
The force required to support the wheelbarrow at the handles, given the combined mass of 100kg and lever arms specified, is approximately 313.64 N, as determined by equilibrium conditions and the principle of moments.
Step-by-step explanation:
The student is asking about the force required to lift a wheelbarrow using principles from physics. Given the combined mass of the wheelbarrow and the load is 100kg, with a center of gravity at d = 0.35m behind the axle and the fact that the handles are 1.1 m behind the axle, we need to calculate the lever arm effect.
The force exerted by the woman at the handles (F) to support the wheelbarrow can be found using the principle of moments (also known as the principle of torques). The moment around the axle due to the gravity should be equal to the moment due to the force exerted by the woman, assuming equilibrium conditions:
Moment due to gravity: Weight × Distance from axle = 100kg × 9.8 m/s² × 0.35m
Moment due to the force at the handles: Force × Distance from axle = F × 1.1m
Setting the two moments equal gives us:
100kg × 9.8 m/s² × 0.35m = F × 1.1m
Solving for F gives:
F = (100kg × 9.8 m/s² × 0.35m) / 1.1m
F = 313.64 N
Therefore, the force required to support the wheelbarrow at the handles is approximately 313.64 N.