Question

From the equation, find the axis of symmetry of the parabola. y=4x²+32x+61.

a. x=3
b. x=−4
c. x=4
d. x=−3

Answer 1

The axis of symmetry of the parabola described by the equation y=4x²+32x+61 is x = -4. So option b is correct.

Step-by-step explanation:

From the equation y=4x²+32x+61, to find the axis of symmetry of the parabola, we use the formula x = -b/(2a), where a and b are coefficients from the quadratic equation in the form y = ax² + bx + c. In this case, a = 4 and b = 32. Plugging these values into the formula, we get:

x = -32 / (2 × 4) = -32 / 8 = -4.

Therefore, the axis of symmetry of the parabola is x = -4.

Or The axis of symmetry of a parabola given by the equation y = ax² + bx + c can be found using the formula x = -b / (2a). In this case, the equation is y = 4x² + 32x + 61, so a = 4, b = 32, and c = 61. Plugging these values into the formula gives x = -32 / (2 * 4) = -4. Therefore, the axis of symmetry is x = -4, so the answer is b. x=−4.