36.3k views
1 vote
Suppose the random variable X has the following probability density function: f(x;k,θ)=kθᵏxᵏ⁻¹,x≥θ.

If k>1, compute E(X).

1 Answer

5 votes

Final answer:

To compute the expected value (E(X)) of a random variable with a given probability density function, we need to multiply each value of X by its probability and add the products. However, in this case, the expected value does not exist for the given probability density function.

Step-by-step explanation:

The random variable X has the probability density function: f(x;k,θ)=kθᵏxᵏ⁻¹,x≥θ, where k > 1. To compute the expected value of X, denoted as E(X), we need to multiply each value of X by its probability and add the products. The formula for E(X) is Σ(x * P(x)). In this case, the values of X are x≥θ, so we need to integrate the probability density function over the range x≥θ. Let's calculate it step by step:

Integrate the probability density function over the range x≥θ: ∫(kθᵏxᵏ⁻¹)dx, from θ to ∞.

Apply the power rule of integration to simplify the integral: kθᵏ∫(xᵏ⁻¹)dx.

Integrate xᵏ⁻¹ with respect to x: kθᵏ * [xᵏ/ᵏ] evaluated from θ to ∞.

Substitute ∞ into the expression: kθᵏ * (∞ᵏ/ᵏ).

Observe that (∞ᵏ) is undefined, so we conclude that the expected value does not exist for this random variable.

User Burak Karasoy
by
7.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.