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The apparant weight of an object while its immersed in a fluid is the difference between its actual weight and the bouyant force. What is the apparant weight of the object if its mass is 745?

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Final answer:

The apparent weight of an object immersed in a fluid is the difference between its actual weight and the buoyant force. By using the formula weight = mass x gravity, we can calculate the actual weight of the object. To find the apparent weight, we need to know the weight of the fluid displaced which requires knowing the density of the fluid.

Step-by-step explanation:

The apparent weight of an object while it is immersed in a fluid is the difference between its actual weight and the buoyant force. The buoyant force is equal to the weight of the fluid displaced by the object. Therefore, the apparent weight of the object is equal to its actual weight minus the weight of the fluid displaced.

Applying this to the problem at hand, if the object has a mass of 745, we can calculate its actual weight using the formula weight = mass x gravity. Let's assume the acceleration due to gravity is 9.8 m/s^2.

Weight = 745 kg x 9.8 m/s^2 = 7291 N (Newtons)

Now, to find the weight of the fluid displaced, we need to know the density of the fluid. With the given information, we can determine the apparent weight of the object by subtracting the weight of the fluid displaced:

Apparent weight = Actual weight - Weight of fluid displaced

Since the specific density of the fluid is not provided, we cannot calculate the apparent weight accurately.

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