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By how much does the value of the 9 exceed the value of the 2 in the numeral 9,027 ?

User Lgomezma
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Final answer:

The value of the 9 in the numeral 9,027 is 9,000, while the value of the 2 is 20. The value of 9 exceeds the value of 2 by 8,980, which is calculated by understanding the place value of each digit.

Step-by-step explanation:

Understanding Place Value in Numerals

When we look at the numeral 9,027 and compare the values of the digits 9 and 2, we need to consider their place values. In the given number, 9 is in the thousands place, which means it represents 9,000. The digit 2 is in the tens place which represents 20.

The value of the 9 exceeds the value of the 2 by 9,000 - 20 = 8,980. The difference in value is due to each digit's position within the numeral, demonstrating the fundamental principle of place value in our base-ten number system.

In general, it is crucial to understand that the position of a digit within a number determines its value, and this is a key concept when performing arithmetic operations and working with significant figures, as seen in various examples provided for context.

User Tomasz Lewowski
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