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What’s the equation of the line that passes threw -4,-3 and 4,-1

User Zts
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Final answer:

The equation of the line that passes through the points (-4, -3) and (4, -1) is y = (1/4)x - 2.

Step-by-step explanation:

To find the equation of the line that passes through the points (-4, -3) and (4, -1), we can use the slope-intercept form of a linear equation, which is y = mx + b. We first need to find the slope (m) of the line using the formula m = (y2 - y1) / (x2 - x1).

Let's substitute the values (-4, -3) and (4, -1) into the formula:

m = (-1 - (-3)) / (4 - (-4))

m = 2 / 8

m = 1/4

Now that we have the slope, we can substitute it and one of the points into the slope-intercept form to find the y-intercept (b).

Using the point (-4, -3):

-3 = (1/4)(-4) + b

-3 = -1 + b

b = -2

Therefore, the equation of the line that passes through the points (-4, -3) and (4, -1) is y = (1/4)x - 2.

User Fencekicker
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