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The maximum speed with which a 1050-kg car makes a 180-degree turn is 15.0 m/s. the radius of the circle through which the car is turning is 30.0 m.

Determine the force of friction acting on the car to keep it moving in a circle
_____N

User Eenoku
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Final answer:

The force of friction required to keep a 1050-kg car moving in a circle at a speed of 15.0 m/s with a radius of 30.0 m is 7875 N. This is the required friction that we want.

Step-by-step explanation:

The student is asking to calculate the force of friction acting on a car to keep it moving in a circle. To determine this, we must use the formula for centripetal force, which is Fc = m*v2/r, where m is the mass of the car, v is the velocity, and r is the radius of the circular path.

The car has a mass of 1050 kg, a maximum speed (velocity, v) of 15.0 m/s, and it is moving in a circular path with a radius (r) of 30.0 m. Plugging these values into the formula, we get:

Fc = (1050 kg)*(15.0 m/s)2/(30.0 m)

Calculating the above expression:

Fc = (1050 kg)*(225 m2/s2)/(30.0 m)

Fc = (1050 kg)*(7.5 m/s2)

Fc = 7875 N

Therefore, the force of friction that acts on the car to keep it moving in a circle is 7875 N.

User Nelewout
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