Final answer:
The force of friction required to keep a 1050-kg car moving in a circle at a speed of 15.0 m/s with a radius of 30.0 m is 7875 N. This is the required friction that we want.
Step-by-step explanation:
The student is asking to calculate the force of friction acting on a car to keep it moving in a circle. To determine this, we must use the formula for centripetal force, which is Fc = m*v2/r, where m is the mass of the car, v is the velocity, and r is the radius of the circular path.
The car has a mass of 1050 kg, a maximum speed (velocity, v) of 15.0 m/s, and it is moving in a circular path with a radius (r) of 30.0 m. Plugging these values into the formula, we get:
Fc = (1050 kg)*(15.0 m/s)2/(30.0 m)
Calculating the above expression:
Fc = (1050 kg)*(225 m2/s2)/(30.0 m)
Fc = (1050 kg)*(7.5 m/s2)
Fc = 7875 N
Therefore, the force of friction that acts on the car to keep it moving in a circle is 7875 N.