Final answer:
To calculate the molar absorptivity of the drug target at 276 nm, use Beer's Law with the provided values to find that the molar absorptivity is 106.32 L·mol⁻¹·cm⁻¹.
Step-by-step explanation:
To calculate the molar absorptivity (extinction coefficient, ε) of your drug target at 276 nm, we can use Beer's Law. Beer's Law states that absorbance (A) is equal to the molar absorptivity (ε) multiplied by the concentration (c) and the path length (l).
In your case, the path length is 1.000 cm, and you provided an absorbance of 10.632 at a concentration of 0.100 M.
The formula to calculate molar absorptivity is:
A = ε × c × l
By rearranging the formula to solve for molar absorptivity, we get:
ε = A / (c × l)
Plugging in your values, we find:
ε = 10.632 / (0.100 mol/L × 1.000 cm) = 106.32 L·mol⁻¹·cm⁻¹.
Therefore, the molar absorptivity of your drug target at 276 nm is 106.32 L·mol⁻¹·cm⁻¹.