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Y′′−3y′ 2y=5et−4tet 6t−3 with initial values y(0)=2andy′(0)=−1.

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Final answer:

The student needs to solve a second-order linear differential equation with given initial conditions, which is a college-level mathematics topic.

Step-by-step explanation:

The student is dealing with a second-order linear differential equation with non-constant coefficients and initial conditions, which is a higher-level mathematics concept typically covered in college courses. The provided equation can be solved by using various methods such as undetermined coefficients or variation of parameters.

Given the initial conditions y(0) = 2 and y'(0) = -1, one can find a particular solution to the nonhomogeneous differential equation and then use the initial conditions to determine the constants in a complementary solution from the homogeneous part of the equation.

The full solution will then be the sum of the homogenous and particular solutions. Although the question contains several typos and irrelevant parts, understanding the key concepts of solving differential equations with initial values is imperative.

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