Question

Is the sum of the areas of two smaller squares equal to the area of a large square if the silencing of the square root of 8’,5’ in 3 feet in the area of a square is s to the power of two where else is the side length?

Answer 1

The area of a larger square is the square of the scale factor times greater than the area of a smaller square with a similar shape. Using the formula 'area = s²', where 's' is the side length, the area scales as the square of the side length increase.

Step-by-step explanation:

The question seems to be about the comparison of areas between geometric shapes, specifically how the area of a larger square compares to the area of smaller squares. To find the area of a square, you use the formula area = s², where s is the side length of the square. For example, if Marta has a square with a side length of 4 inches, and another square with dimensions that are twice the first square, the side length of the larger square would be 8 inches (4 inches x 2).

When comparing the areas of two squares, where one has a side length that is a scale factor of another, the area of the larger square will be the square of the scale factor times larger. In Marta's case, the larger square has an area that is 4 times greater than the smaller square because the scale factor (2) squared is 4 (2² = 4).

In general, when the side lengths are scaled by a certain factor, the areas of squares are scaled by the square of that factor. This rule helps to quickly determine how areas of similar geometric shapes compare as they scale in size.