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Use the equation C₃H₈ + O₂ → CO₂ + H₂O to answer the following question

How many moles of Propane (C₃H₈) are needed to produce 25 moles of carbon dioxide?

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Final answer:

To produce 25 moles of carbon dioxide from the combustion of propane, 8.33 moles of propane are needed, based on the stoichiometric ratio of 1 mole of C3H8 producing 3 moles of CO2.

Step-by-step explanation:

In the balanced equation C₃H₈ + O₂ → CO₂ + H₂O, the stoichiometric ratio between propane (C₃H₈) and carbon dioxide (CO₂) is 1:3. This means that for every mole of propane, three moles of carbon dioxide are produced.

Therefore, to produce 25 moles of carbon dioxide, you would need (25 moles CO₂) ÷ (3 moles C₃H₈/mol CO₂) = 8.33 moles of propane. Since moles cannot be measured in fractions, you would round up to 9 moles of propane.

So, you would need 9 moles of propane to produce 25 moles of carbon dioxide.

To determine how many moles of Propane (C3H8) are needed to produce 25 moles of carbon dioxide (CO2), we can use the balanced chemical equation for the combustion of propane, which is: C3H8 + 5 O2 → 3 CO2 + 4 H2O. This equation indicates that 1 mole of propane produces 3 moles of carbon dioxide. Therefore, using stoichiometry and the stoichiometric factor provided, we can calculate the required moles of propane:

3 mol CO2 / 1 mol C3H8 = 25 mol CO2 / x mol C3H8

Solving for x gives us x = 25 mol CO2 / 3 = 8.33 moles of propane. Hence, to produce 25 moles of carbon dioxide, 8.33 moles of propane are needed.

User Chad Zawistowski
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