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Use the drop-down menus to choose steps in order to correctly solve 1 2−13=12−4−2 for .

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Solve 1 + 2b - 13 = 12 - 4b - 2b, simplify both sides, combine like terms, and isolate the variable. The solution is b = 3.

To solve the equation 1 + 2b - 13 = 12 - 4b - 2b:

Step 1: Simplify constants on the left-hand side (LHS):


\[2b + (1 - 13) = 12 - 4b - 2b \implies 2b - 12 = 12 - 4b - 2b\]

Step 2: Simplify variable terms on the right-hand side (RHS):


\[2b - 12 = 12 + (-4b - 2b) \implies 2b - 12 = 12 - 6b\]

Step 3: Transpose \(-6b\) from RHS to LHS:

2b - 12 + 6b = 12

Step 4: Simplify variable terms on the LHS:

8b - 12 = 12

Step 5: Transpose 12 to the RHS:

8b = 12 + 12

Step 6: Simplify constants on the RHS:

8b = 24

Step 7: Transpose 8 to the RHS:


\[b = (24)/(8)\]

Step 8: Simplify the fraction:

b = 3

Therefore, the solution to the equation is b = 3.

Que. Use the drop-down menus to choose steps in order to correctly solve 1+2b−13=12−4b−2b1+2b-13=12-4b-2b for b.

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