Solve 1 + 2b - 13 = 12 - 4b - 2b, simplify both sides, combine like terms, and isolate the variable. The solution is b = 3.
To solve the equation 1 + 2b - 13 = 12 - 4b - 2b:
Step 1: Simplify constants on the left-hand side (LHS):
![\[2b + (1 - 13) = 12 - 4b - 2b \implies 2b - 12 = 12 - 4b - 2b\]](https://img.qammunity.org/2024/formulas/mathematics/high-school/9o6a9hq9s0eguosttsrlzqkl2xq8z1l7z1.png)
Step 2: Simplify variable terms on the right-hand side (RHS):
![\[2b - 12 = 12 + (-4b - 2b) \implies 2b - 12 = 12 - 6b\]](https://img.qammunity.org/2024/formulas/mathematics/high-school/xsz3ipdinje28psbynp0330vkr1e6j926s.png)
Step 3: Transpose \(-6b\) from RHS to LHS:
2b - 12 + 6b = 12
Step 4: Simplify variable terms on the LHS:
8b - 12 = 12
Step 5: Transpose 12 to the RHS:
8b = 12 + 12
Step 6: Simplify constants on the RHS:
8b = 24
Step 7: Transpose 8 to the RHS:
![\[b = (24)/(8)\]](https://img.qammunity.org/2024/formulas/mathematics/high-school/xmqczw4zcfhaw82f0c321qtouensck5xfi.png)
Step 8: Simplify the fraction:
b = 3
Therefore, the solution to the equation is b = 3.
Que. Use the drop-down menus to choose steps in order to correctly solve 1+2b−13=12−4b−2b1+2b-13=12-4b-2b for b.