Question

You will randomly determine each parents’ genotype by rolling the die. any even number means they parent has a dominant (f) allele. any odd number means they will have a recessive (f) allele. this means you will roll the die twice for each parent to determine which two alleles they will have. once you have determined the genotype of each parent complete the dihybrid cross to determine the possible genotypes of their offspring. parent 1: parent 2:

Answer 1

The student's question is about determining the possible genotypes and phenotypes of offspring in genetic crosses using Punnett squares and Mendelian genetics.

Step-by-step explanation:

The question pertains to genetics, specifically to the Punnett square method used to predict the outcomes of crosses between organisms to find the possible genotypes and phenotypes of their offspring, considering dominant and recessive alleles. Various monohybrid crosses, including true-breeding parents with a pair of contrasting alleles (e.g., YY and yy) and self-cross of heterozygous offspring (e.g., Yy), were mentioned. The probability rules, such as the segregation of alleles into gametes and the random combination of these alleles during fertilization, play a critical role in these genetic predictions, which are well exemplified in Mendelian inheritance patterns.

To determine the possible genotypes of offspring, we need to determine the genotypes of Parent 1 and Parent 2. Each allele is represented by an even number (dominant) or odd number (recessive) when rolling a die. Rolling the die twice for each parent will give us their genotypes.

For example, if Parent 1 rolls a 2 and a 4, they will have the genotype FF. Parent 2 can roll a 1 and a 3, giving them the genotype Ff. Using this information, we can complete the dihybrid cross and determine the possible genotypes of their offspring.