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A block of dry ice slides at a constant velocity on a smooth, horizontal, frictionless surface. A second block of dry ice slides twice as fast on the same surface (at a higher constant velocity).

Compare the resultant forces exerted on each block.

O The resultant force exerted on the first block is less than the resultant force on the second block.
O The resultant force exerted on the first block and the resultant force on the second block are both zero.
O The resultant force exerted on the first block is greater than the resultant force on the second block.
O None of the above.

User Imran Omer
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1 Answer

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Final answer:

The resultant force exerted on the first block is less than the resultant force on the second block. Option 1 is correct.

Step-by-step explanation:

The resultant force exerted on the first block is less than the resultant force on the second block.

When a block of dry ice slides at a constant velocity on a smooth, horizontal, frictionless surface, the resultant force acting on it is zero. This is because the force of gravity pulling the block downward is balanced by the normal force exerted by the surface upward.

If the second block of dry ice slides twice as fast as the first block, it means the velocity of the second block is greater. Since the frictional force is dependent on the velocity of the block, the second block will experience a greater frictional force compared to the first block. Hence, the resultant force exerted on the second block is greater than the resultant force on the first block.

User Jeffrey Forbes
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