Question

Ammonia reacts with oxygen according to the reaction 4NH₃(g)+5O₂(g)→4NO(g)+6H₂O(g),ΔHrxn=−906kJ Calculate the heat associated with the complete reaction of 155 g of NH₃.

Answer 1

To find the heat associated with the complete reaction of 155 g of NH₃, we need to calculate the moles of NH₃ and use the stoichiometry of the reaction. The heat associated with 155 g of NH₃ is -2067 kJ.

Step-by-step explanation:

To calculate the heat associated with the complete reaction of 155 g of NH₃, we need to use the given enthalpy change of the reaction and the stoichiometry of the reaction.

The equation for the reaction is: 4 NH₃(g) + 5 O₂(g) → 4 NO(g) + 6 H₂O(g)

The enthalpy change (ΔHrxn) is -906 kJ. This means that the reaction is exothermic, and 906 kJ of heat is released.

To find the heat associated with 155 g of NH₃, we need to calculate the moles of NH₃ using its molar mass (17 g/mol).

Moles of NH₃ = 155 g NH₃ / 17 g/mol = 9.12 mol NH₃. Now we can use the stoichiometry of the reaction to find the heat associated with 9.12 mol of NH₃. From the balanced equation, we can see that 4 mol of NH₃ produces -906 kJ of heat.

So, 9.12 mol of NH₃ will produce (9.12 mol NH₃ / 4 mol NH₃) * -906 kJ = -2067 kJ of heat.