Final answer:
The maximum height attained by a 5 kg ball thrown upwards with a speed of 10 m/s is approximately 5.1 meters, which makes option A, 5 m, the closest answer. Option A is correct.
Step-by-step explanation:
The subject of the question is Physics, focusing specifically on the concept of projectile motion under the influence of gravity. The question is at a High School level and relates to the calculation of the maximum height attained by a projectile, which in this case is a ball.
To calculate the maximum height (h) attained by the ball, we use the conservation of energy principle or the kinematic equations for uniformly accelerated motion. Using the kinematic equation v^2 = u^2 + 2gh, where v is the final velocity (0 m/s at the maximum height), u is the initial velocity (10 m/s), and g is the acceleration due to gravity (-9.81 m/s^2), we can rearrange the formula to solve for the maximum height h:
0 = (10 m/s)^2 - 2(9.81 m/s^2)(h)
Solving for h gives us:
h = (10 m/s)^2 / (2 × 9.81 m/s^2)
h = 5.1 m
The maximum height attained by the ball would be approximately 5.1 meters, which is closest to option A, 5 m.