Question

14x - 4y = 40
7x + 8y = -10

Answer 1

The question involves solving a system of linear equations, a high school algebra topic. Using the elimination method, the solution obtained is x = 2 and y = -3.

Step-by-step explanation:

The question presented requires solving a system of linear equations, which is a common topic in high school algebra. The system given is:

1) 14x - 4y = 40
2) 7x + 8y = -10

To solve this, we can use the method of substitution or elimination. Let's use elimination as an example:

1. Multiply the second equation by 2 to get the coefficients of y to match:
   2 * (7x + 8y) = 2 * -10
   14x + 16y = -20
2. Now, subtract this from the first equation to eliminate y:
   (14x - 4y) - (14x + 16y) = 40 - (-20)
   -20y = 60
3. Divide both sides by -20 to find the value of y:
   y = -3
4. Substitute y = -3 into one of the original equations to find x:
   7x + 8(-3) = -10
   7x - 24 = -10
   7x = 14
   x = 2

Thus, the solution to the system of equations is x = 2 and y = -3.