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Find the slope of a line perpendicular to the line whose equation is 3, x, plus, 18, y, equals, 1083x 18y=108.

User Lifely
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Final answer:

The slope of the original line 3x + 18y = 108 is -1/6. The slope of a line perpendicular to this is the negative reciprocal, which is 6.

Step-by-step explanation:

To find the slope of a line perpendicular to the given line, we first need to identify the slope of the original line. The equation provided is 3x + 18y = 108, which can be rewritten in slope-intercept form (y = mx + b), where m represents the slope, and b represents the y-intercept.

First, we solve for y:

  • 18y = -3x + 108
  • y = (-3x/18) + (108/18)
  • y = -1/6x + 6

The slope of the original line is -1/6. The slope of a line perpendicular to this would be the negative reciprocal. Therefore:

  • The negative reciprocal of -1/6 is 6

The slope of a line perpendicular to the given line is 6.

User SuperManEver
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