Final answer:
For the reaction 2Cr(s) + 3Cu²⁺ (aq) → 2Cr³⁺ (aq) + 3Cu(s), the half-reaction occurring at the cathode, where reduction takes place, is 3Cu²⁺(aq) + 6e⁻ → 3Cu(s). The correct answer is A. 3Cu₂⁺(aq) + 6e⁻ → 3Cu(s).
Step-by-step explanation:
In a galvanic cell, the oxidation reaction occurs at the anode, and the reduction reaction occurs at the cathode. For the given reaction 2Cr(s) + 3Cu²⁺ (aq) → 2Cr³⁺ (aq) + 3Cu(s), we can separate this into the two half-reactions representing oxidation and reduction processes.
The reduction half-reaction involves the gain of electrons and will occur at the cathode. Therefore, the correct half-reaction that occurs at the cathode is A. 3Cu²⁺(aq) + 6e⁻ → 3Cu(s).
A galvanic cell, also known as a voltaic cell, is an electrochemical cell that generates electrical energy from spontaneous chemical reactions.
It consists of two different metal electrodes (anode and cathode) connected by an electrolyte solution or salt bridge, allowing the flow of ions to complete the circuit.