Final answer:
The compound CH3CCl2CH3 does not exhibit optical isomerism because it lacks a chiral center, which requires a carbon with four different substituents. The correctanswer is b. no.
Step-by-step explanation:
To determine whether the compound CH₃CCl₂CH₃ exhibits optical isomerism, we must assess if it has a chiral center, which is a carbon atom with four different substituents. Looking at the structure of this compound, we see that it has two chlorine atoms attached to the same carbon.
Because this carbon does not have four different substituents, it is not chiral, and thus, the compound cannot exhibit optical isomerism.
CH₃CCl₂CH₃ is a compound with a central carbon atom bonded to two chlorine atoms and two methyl groups. For a compound to exhibit optical isomerism, it needs to have at least one chiral center.
A chiral center is a carbon atom bonded to four different groups. In the case of CH₃CCl₂CH₃, the central carbon atom is bonded to two chlorine atoms and two methyl groups, which are not different. Therefore, this compound does not exhibit optical isomerism.