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1 vote

4 * 8 ^(2x + 1?) = 32 ^(x + 2)


User Scandel
by
3.4k points

1 Answer

5 votes

Answer:

x = 5

Explanation:

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FACTS TO KNOW BEFORE SOLVING :-


  • a^x * a^y = a^(x+y)
  • In an equation , if the bases are same in both L.H.S. & R.H.S. then , the power of the bases on both the sides of equation should be equal. For e.g. :
    a^x = a^y
    x = y [∵ Bases are equal on both the sides]

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4 * 8^(2x+1) = 32^(x+2)

Lets express it in terms of 2.


=> 2^2 * 2^(3 (2x+1)) = 2^(5(x+2))


=> 2^2 * 2^(6x+3) = 2^(5x+10)


=> 2^(2 + 6x+3) = 2^(5x+10)


=> 2^(6x+5) = 2^(5x+10)

Here the bases on both the sides are equal. Hence ,


=> 6x + 5 = 5x + 10


=> 6x - 5x = 10 - 5


=> x = 5

User Anderson Pimentel
by
3.9k points