Question

Which value of x satisfies the equation start fraction, 6, divided by, 5, end fraction, left bracket, x, plus, start fraction, 3, divided by, 2, end fraction, right bracket, equals, minus, 3 5 6 ​ (x 2 3 ​ )=−3?

A. x = -9
B. x = -6
C. x = -3
D. x = 0
E. x = 3

Answer 1

Which value of x satisfies the equation: (6/5)(x + 3/2) = -3 is x = -4.

We can write mathematically the equation: start fraction, 6, divided by, 5, end fraction, left bracket, x, plus, start fraction, 3, divided by, 2, end fraction, right bracket, equals, minus, 3 as;

(6/5)(x + 3/2) = -3

Thus we can solve for x as follows:

6x/5 + 18/10 = -3 {open bracket}

(12x + 18)/10 = -3 {simplify the fractions to one}

12x + 18 = -3 × 10 {cross multiplication}

12x + 18 = -30

12x = -30 - 18

12x = -48

x = -48/12 {divide through by 12}

x = -4.

Therefore, the value of which satisfies the equation: (6/5)(x + 3/2) = -3 is derived to be -4.