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Which of the following equations have infinitely many solutions? Choose all answers that apply:

O 6x+35=-6x+35
O -6x+35=-6x-35
O -6x+35=-6x+35
O 6x+35=-6x-35

User Leon V
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4 votes

Final answer:

The equation with infinitely many solutions is -6x+35=-6x+35, because after simplifying, both sides are identical, which results in the identity 35=35. Option 3 is correct.

Step-by-step explanation:

To determine which of the listed equations have infinitely many solutions, we look for equations where both sides are identical after simplification. Let's analyze each equation:

6x+35=-6x+35: On simplifying, we add 6x to both sides to get 12x+35=35. This does not result in an identity, so it does not have infinitely many solutions.

-6x+35=-6x-35: This has no solutions, because when the -6x terms cancel out, we are left with 35=-35, which is not true.

-6x+35=-6x+35: After eliminating the -6x terms on both sides, we have an identity, 35=35, which means this equation has infinitely many solutions.

6x+35=-6x-35: Simplifying similarly, we'll find that this equation cannot be true for any value of x, since 6x cannot equal -6x unless x=0, and even then, 35 cannot equal -35.

Therefore, the equation with infinitely many solutions is -6x+35=-6x+35.

User Ganjeii
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